Re: Problem with multipart/x-mixed replace

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I think you will find that IE does not support  "multipart/x-mixed-repl=
ace"
despite its claim of "User-Agent:=A0 Mozilla/4.0 (compatible..."

You might try asking over on www-talk (see
http://lists.w3.org/Archives/Public/www-talk/).

     -Carl



                                                                       =
                                            =20
                    "Seema P Kumar"                                    =
                                            =20
                    <2kseema@sun20.datam       To:     <http-wg@cuckoo.=
hpl.hp.com>                                 =20
                    atics.com>                 cc:                     =
                                            =20
                                               Subject:     Problem wit=
h multipart/x-mixed replace                 =20
                    03/30/2001 04:41 AM                                =
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Hi all !

=A0Could anybody tell me about the  "multipart/x-mixed-replace" content=
 type
?
=A0I try to use thie content  type for my HTTPServletResponse object in=
 my
Java servlet, to  keep
=A0outputting messages to
=A0the browser, but however, the  browser does not interpret the header=
s
=A0properly and all the tags are  visible as
=A0part of the browser content (I use Internet Explorer  5.0).

The following is the Java code :
public class RefreshingServlet extends  HttpServlet{


=A0public void init(ServletConfig config)  throws  ServletException{
=A0=A0super.init(config);

=A0}

public void service(HttpServletRequest req,  HttpServletResponse res)
=A0=A0=A0 throws ServletException,  IOException
{
=A0=A0=A0  res.setContentType("multipart/x-mixed-replace;boundary=3D\"b=
oundary\"");

=A0=A0PrintWriter out=3Dres.getWriter();
=A0=A0=A0 // Here  is the first part
=A0=A0=A0  out.print("\n\r--boundary\n\r");
=A0=A0=A0 out.print("Content-Type:  text/html\n\r");

=A0=A0=A0  out.println("<H1>Waiting...</H1>");
=A0=A0=A0  out.flush();

=A0=A0=A0 // Here is the long work (here,  a sleep)
=A0=A0=A0 try
=A0=A0=A0=A0=A0=A0=A0=A0  Thread.sleep(3000);
=A0=A0=A0 }
=A0=A0=A0 catch  (Exception e) {
=A0=A0=A0=A0=A0=A0=A0=A0 //  ignore
=A0=A0=A0 }

=A0=A0=A0 // Here is the second  part
=A0=A0=A0  out.print("\n\r--boundary\n\r");
=A0=A0=A0 out.print("Content-Type:  text/html\n\r");

=A0=A0=A0  out.println("<H1>Done</H1>");

=A0=A0=A0  out.print("\n\r--boundary--\n\r");
=A0=A0=A0  out.flush();
}

}

Any loopholes for this ?

Regards,
Seema Kumar
Datamatics Technologies  Ltd.,
(Tel: 8290829 (Ext:619))

=

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